See complete series on data structures here:
In this lesson, we have discussed array based implementation of stack data structure.
C code: https://gist.github.com/mycodeschool/6878252
C++ code (Object oriented implementation) : https://gist.github.com/mycodeschool/6878628
Time complexity of push for dynamic array implementation:
If we start with an array of size 1 and keep doubling the size with each overflow, for n pushes.. cost of copy will be
(1 + 2 + 4 + 8 + ... + n/2 + n)
= n *( 1+ 1/2 + 1/4 + 1/8 + ... 1/n) - taking out n
= n*2 - the expression in bracket above will evaluate to 2.
So, cost of copy in n pushes = O(n)
Cost of n normal pushes = O(n) - each push takes constant time
Total cost of n pushes = O(n)
Average cost of 1 push = O(1).
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3 years ago